64x^2-256=0

Solution for 64x^2-256=0 equation:

64x^2-256=0

a = 64; b = 0; c = -256;
Δ = b2-4ac
Δ = 02-4·64·(-256)
Δ = 65536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65536}=256$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-256}{2*64}=\frac{-256}{128}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+256}{2*64}=\frac{256}{128}
=2
$